b^2-7b+20=0

Solution for b^2-7b+20=0 equation:

Simplifying
b2 + -7b + 20 = 0

Reorder the terms:
20 + -7b + b2 = 0

Solving
20 + -7b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -7b + -20 + b2 = 0 + -20

Reorder the terms:
20 + -20 + -7b + b2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -7b + b2 = 0 + -20
-7b + b2 = 0 + -20

Combine like terms: 0 + -20 = -20
-7b + b2 = -20

The b term is -7b.  Take half its coefficient (-3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
-7b + 12.25 + b2 = -20 + 12.25

Reorder the terms:
12.25 + -7b + b2 = -20 + 12.25

Combine like terms: -20 + 12.25 = -7.75
12.25 + -7b + b2 = -7.75

Factor a perfect square on the left side:
(b + -3.5)(b + -3.5) = -7.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.